# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def buildTree(self, preorder: List[int], inorder: List[int]) -> TreeNode:
if not preorder: return None
root = TreeNode(preorder[0])
cur = inorder.index(root.val)
#跳过根节
六.二叉树构造
于 2022-01-07 14:30:03 首次发布